Parents can use OP Malhotra Class 9 Solutions Chapter 4 Factorisation Ex 4(C) to provide additional support to their children.

## S Chand Class 9 ICSE Maths Solutions Chapter 4 Factorisation Ex 4(C)

Factorise :

Question 1.
x² + 4x + 4
Solution:
x² + 4x + 4
= (x)² + 2 × x × 2 + (2)²
= (x + 2)²

Question 2.
x² + 6x + 9
Solution:
x² + 6x + 9
= (x)² + 2 x x x 3 + (3)² = (x + 3)²

Question 3.
x² – 10x + 25
Solution:
x² – 10x + 25
= (x)² – 2 × x × 5 + (5)²
= (x – 5)²

Question 4.
4x² – 4x + 1
Solution:
4x² – 4x + 1
= (2x)² – 2 × 2x × 1 + (1)²
= (2x – 1)²

Question 5.
1 – 8x + 16x²
Solution:
1 – 8x + 16x²
= (1)² – 2 x 1 x 4x + (4x)²
= (1 – 4x)²

Question 6.
49x4 + 168x²y² + 144y4
Solution:
49x4 + 168x²y² + 144y4
= (7x²)² + 2 x 7x² x 12y² + (12y)²
= (7x² + 12y²)²

Question 7.
x² + x + $$\frac { 1 }{ 4 }$$
Solution:
x² + x + $$\frac { 1 }{ 4 }$$
= (x)² + 2 × x × $$\frac { 1 }{ 2 }$$ + ($$\frac { 1 }{ 2 }$$)²
= (x + $$\frac { 1 }{ 2 }$$)²

Question 8.
25p² + $$\frac { 5p }{ 2q }$$ + $$\frac { 1 }{ 16q² }$$
Solution:
25p² + $$\frac { 5p }{ 2q }$$ + $$\frac { 1 }{ 16q² }$$
= (5p)² + 2 x 5p x $$\frac { 1 }{ 4q }$$ x ($$\frac { 1 }{ 4q }$$)²
= (5p + $$\frac { 1 }{ 4q }$$)²