Regular engagement with OP Malhotra Class 9 Solutions Chapter 4 Factorisation Ex 4(A) can boost students confidence in the subject.

## S Chand Class 9 ICSE Maths Solutions Chapter 4 Factorisation Ex 4(A)

Factorise :

Question 1.
8x + 16y
Solution:
8x + 16y – 8 (x – 2y)

Question 2.
ax – 2ay
Solution:
ax – 2ay = a (x – 2y)

Question 3.
25xy – 50y
Solution:
15xy – 50y = 25y (x – 2)
(H.C.F. of 25, 50 = 25)

Question 4.
abc – ac
Solution:
abc – ac = ac (b – 1)

Question 5.
– 121 – 11m²
Solution:
– 121 w – 11m²
= 11 m (- 11 – m) (H.C.F. of 121, 11, = 11)

Question 6.
a²b + ab²
Solution:
a²b + ab² = ab (a + b)

Question 7.
24x³y – 30x²y
Solution:
24x³y – 30x²y = 6x²y (4x – 5)
(H.C.F. of 24, 30 = 6)

Question 8.
– 9x³ – 12x² + 3x
Solution:
– 9x³ – 12x² + 3x = – 3x (3x² + 4x – 1)
(H.C.F. of 9, 12, 3 = 3)

Question 9.
25a²bc³ – 35ab²c³ + 45a³bc²
Solution:
25a²bc³ – 35ab²c³ + 45a³bc²
(H.C.F. of 25, 35, 45 = 5)
= 5abc² (5ac – 7bc + 9a²)

Question 10.
– x – y – z
Solution:
– x – y – z = – 1 (x + y + z)

Question 11.
x(x – y) + (x – y)
Solution:
x (x – y) + (x – y) – (x – y) (x + 1)

Question 12.
(x + y) – (x + y)²
Solution:
(x + y) – (x + y)² = (x + y) – (x + y) (x + y)
= (x + y) (1 – x – y) .

Question 13.
a (x – y) – b (y – x)
Solution:
a (x – y) – b (y – x) = a (x – y) + b (x – y) = (x – y) (a + b)

Question 14.
(a – b)4 + (a – b)³
Solution:
(a – b)4 + (a – b)³ = (a – b)³ [(a – b) + 1 ]
= (a – b)³ (a – b + 1)

Question 15.
(x – y)6 + (y – x)5
Solution:
(x – y)6 + (y – x)5 = (x – y)6 – (x – y)5
= (x – y)5 (x – y – 1)