{"id":43445,"date":"2023-04-12T10:50:49","date_gmt":"2023-04-12T05:20:49","guid":{"rendered":"https:\/\/icsesolutions.com\/?p=43445"},"modified":"2023-04-13T10:42:07","modified_gmt":"2023-04-13T05:12:07","slug":"ml-aggarwal-class-6-solutions-for-icse-maths-chapter-8-check-your-progress","status":"publish","type":"post","link":"https:\/\/icsesolutions.com\/ml-aggarwal-class-6-solutions-for-icse-maths-chapter-8-check-your-progress\/","title":{"rendered":"ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 8 Ratio and Proportion Check Your Progress"},"content":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 8 Ratio and Proportion Check Your Progress<\/h2>\n

Question 1.
\nFrom the given figure, find the ratio of
\n\"ML
\n(i) Number of triangles to the number of circles inside the rectangle.
\n(ii) Number of squares to the number of all the figures inside the rectangle.
\n(iii) Number of circles to the number of remaining figures inside the rectangle.
\nSolution:
\nNumber of triangles = 3
\nNumber of rectangles = 2
\nNumber of circles = 2
\n(i) 3 : 2
\n(ii) 2 : 7
\n(iii) 2 : 5<\/p>\n

Question 2.
\nThe length of a pencil is 16 cm and its diameter is 6 mm. What is the ratio of the diameter of the pencil to that of its length?
\nSolution:
\nLength of a pencil = 16 cm = 16 cm \u00d7 10 = 160 mm
\nDiameter of the pencil = 6 mm
\nRatio of the diameter of the pencil to that of its length = 6 : 160 = 3 : 80<\/p>\n

Question 3.
\nA certain club has 100 members, out of which 25 play tennis, 28 play badminton, 12 play chess and the rest do not play any game. Find the ratio of number of members who play
\n(i) badminton to the number of those who play chess.
\n(ii) badminton to the number of those who do not play any game.
\n(iii) tennis to the number of those who do not play any game.
\n(iv) tennis to the number of those who play either badminton or chess.
\nSolution:
\nTotal number of members = 100
\nMembers who plays tennis = 25
\nMembers who plays badminton = 28
\nMembers who plays chess = 12
\nMembers who play nothing = 100 – (25 + 28 + 12)
\n= 35
\n(i) 28 : 12 = 7 : 3
\n(ii) 28 : 35 = 4 : 5
\n(iii) 25 : 28 = 5 : 7
\n(iv) 25 : 40 = 5 : 8<\/p>\n

Question 4.
\nDo the ratios 15 cm to 3 m and 25 seconds to 3 minutes from a proportion?
\nSolution:
\nGiven, first ratio = 15 cm : 3 m
\n= 15 cm : 300 cm
\n= 1 : 20
\nand second ratio = 25 seconds : 3 minutes
\n= 25 seconds : 3 \u00d7 60 seconds
\n= 25 : 180 = 1 : 6
\nNo, they do not form proportion.<\/p>\n

Question 5.
\nDivide \u20b9500 among Suresh and Awanti in the ratio 3 : 7.
\nSolution:
\nTotal amount = \u20b9500
\nRatio = 3 : 7
\nSum of ratios = 3 + 7=10
\nSuresh shares = \u20b9\\(\\frac{500 \\times 3}{10}\\) = \u20b9150
\nAwanti shares = \u20b9 \\(\\frac{500 \\times 7}{10}\\) = \u20b9350<\/p>\n

Question 6.
\nThe ratio of the number of girls to that of boys in a school is 9 : 11. If the number of boys in the school is 2035, find:
\n(i) the number of girls in the school,
\n(ii) the number of students in the school.
\nSolution:
\nLet the number of girls = x
\nGirls : Boys = 9 : 11
\nNo. of boys = 2035
\nx : 2035 = 9 : 11
\n\"ML
\nNo. of girls = 1665.
\n(ii) Total students in school = No. of boys + No. of girls
\n2035 + 1665 = 3700<\/p>\n

Question 7.
\nThe ratio of income to expenditure of a family is 7 : 6. Find the savings if the income of family is \u20b942000.
\nSolution:
\nRatio in income and expenditure = 7 : 6
\nTotal income = \u20b942000
\nLet expenditure = x, then
\n7 : 6 :: 42000 : x
\n\u21d2 \\(x=\\frac{6 \\times 42000}{7}\\) = \u20b936000
\nNow,
\nIncome = \u20b942000
\nExpenditure = \u20b936000
\n\u2234 Savings = Income – Expenditure
\n= \u20b9(42000 – 36000) = \u20b96000<\/p>\n

Question 8.
\nAn employee earns \u20b972,000 in 3 months.
\n(i) How much does he earn in 7 months?
\n(ii) In how many months will he earn \u20b93,60,000?
\nSolution:
\n(i) \u2235 Earning in 3 months = \u20b972000
\n\u2234 Earning in 1 month = \u20b9\\(\\frac{72000}{3}\\) = 24000
\nEarning in 7 months = \u20b924000 \u00d7 7
\n= \u20b91,68,000
\n(ii) \u20b924000 is earned in = 1 month
\n\u20b91 is earned is = \\(\\frac{1}{24000}\\)
\n\u20b93,60,000 is earned in
\n\"ML<\/p>\n

Question 9.
\nA train travels 110 km in 2 hours and a car travels 245 km in \\(3 \\frac{1}{2}\\) hours. What is the ratio of the speed of the train to that of the car?
\nSolution:
\nA train travels in 2 hours =110 km
\nIt will cover in 1 hour = \\(\\frac{110}{2}\\) = 55 km
\nA car travel in \\(\\frac{7}{2}\\) hours = 245 km
\n\u2234 It will cover in 1 hour =\\(\\frac{2 \\times 245}{7}\\) = 70 km
\nRatios in their speed = 55 : 70 = 11 : 14<\/p>\n

ML Aggarwal Class 6 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 8 Ratio and Proportion Check Your Progress Question 1. From the given figure, find the ratio of (i) Number of triangles to the number of circles inside the rectangle. (ii) Number of squares to the number of all the figures inside the rectangle. (iii) Number of …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43445"}],"collection":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/comments?post=43445"}],"version-history":[{"count":1,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43445\/revisions"}],"predecessor-version":[{"id":159071,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43445\/revisions\/159071"}],"wp:attachment":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/media?parent=43445"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/categories?post=43445"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/tags?post=43445"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}