{"id":43099,"date":"2023-04-09T13:19:39","date_gmt":"2023-04-09T07:49:39","guid":{"rendered":"https:\/\/icsesolutions.com\/?p=43099"},"modified":"2023-04-10T09:53:02","modified_gmt":"2023-04-10T04:23:02","slug":"ml-aggarwal-class-6-solutions-for-icse-maths-chapter-6-ex-6-7","status":"publish","type":"post","link":"https:\/\/icsesolutions.com\/ml-aggarwal-class-6-solutions-for-icse-maths-chapter-6-ex-6-7\/","title":{"rendered":"ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 6 Fractions Ex 6.7"},"content":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 6 Fractions Ex 6.7<\/h2>\n

Question 1.
\nSarita bought \\(\\frac{2}{5}\\) metre of ribbon and Laiita \\(\\frac{3}{4}\\) metre of ribbon. What is the total length of the ribbon they bought?
\nSolution:
\nRibbon bought by Sarita = \\(\\frac{2}{5}\\) m
\nRibbon bought by Lai ita = \\(\\frac{3}{4}\\) m
\n\u2234 Total length of the ribbon they bought
\n\"ML<\/p>\n

Question 2.
\nA bamboo of length \\(2 \\frac{3}{4}\\) metre broke into two pieces. One piece was \\(\\frac{7}{8}\\) metre long. How long is the other piece?
\nSolution:
\nLet of original piece of bamboo = \\(2 \\frac{3}{4}\\) = \\(\\frac{11}{4}\\) metre
\nLength of one piece = \\(\\frac{7}{8}\\) metre
\nLength of other piece = \\(\\frac{7}{8}\\) metre – \\(\\frac{7}{8}\\) metre
\n\"ML<\/p>\n

Question 3.
\nNidhi’s house is \\(1 \\frac{9}{10}\\) km from her school. She walked some distance and then took a bus for \\(1 \\frac{1}{2}\\) km to reach the school. How far did she walk?
\nSolution:
\nDistance of Nidhi’s house from school
\n\\(=1 \\frac{9}{10} \\mathrm{km}=\\frac{19}{10} \\mathrm{km}\\)
\n\"ML<\/p>\n

Question 4.
\nFrom a rope of length \\(20 \\frac{1}{2}\\) m, a piece of length \\(3 \\frac{5}{8}\\) m is cut off. Find the length of the remaining rope.
\nSolution:
\nTotal length of rope = \\(20 \\frac{1}{2}\\) m
\nLength cut off = \\(3 \\frac{5}{8}\\) m
\n\"ML
\n\u2234 Length of the remaining rope = \\(16 \\frac{7}{8}\\) m<\/p>\n

Question 5.
\nThe weight of three packets are \\(2 \\frac{3}{4}\\) kg. \\(3 \\frac{1}{3}\\) kg. and \\(5 \\frac{2}{5}\\) kg. Find total weight of all the three packets.
\nSolution:
\nWeight of 1st packet = \\(2 \\frac{3}{4}\\)
\nWeight of 2nd packet = \\(3 \\frac{1}{3}\\)
\nWeight of 3rd packet = \\(5 \\frac{2}{5}\\)
\n\u2234 Total weight
\n\"ML<\/p>\n

Question 6.
\nShivani read 25 pages of a book containing 100 pages. Nandni read \\(\\frac{2}{5}\\) of the same book. Who read less?
\nSolution:
\nShivani read pages = \\(\\frac{25}{100}=\\frac{1}{4}\\)
\nNandni read pages = \\(\\frac{2}{5}\\)
\nNow, LCM of 4 and 5 = 20
\nMaking \\(\\frac{1}{4} \\text { and } \\frac{2}{5}\\) as like fractions
\n\"ML
\n\"ML
\n\u2234 Shivani read less pages than Nandni.<\/p>\n

Question 7.
\nRafiq exercised for \\(\\frac{3}{6}\\) of an hour, while Rohit, exercised for \\(\\frac{3}{4}\\) of an hour. Who exercised for a longer time and by what fraction of an hour?
\nSolution:
\nRafiq exercised for \\(\\frac{3}{6}\\) of an hour
\n= \\(\\frac{1}{2}\\) of an hour
\nRohit exercised for \\(\\frac{3}{4}\\) of an hour
\n= \\(\\frac{3}{4}\\) of an hour
\nLCM of 2 and 4 = 4
\n\"ML
\nRafiq’s exercise < Rohit’s exercise
\nMore exercise done by Rohit in fraction
\n\"ML
\nRohit does exercise more then Rafiq by \\(\\frac{1}{4}\\) of an hour.<\/p>\n

ML Aggarwal Class 6 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 6 Fractions Ex 6.7 Question 1. Sarita bought metre of ribbon and Laiita metre of ribbon. What is the total length of the ribbon they bought? Solution: Ribbon bought by Sarita = m Ribbon bought by Lai ita = m \u2234 Total length of the ribbon …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43099"}],"collection":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/comments?post=43099"}],"version-history":[{"count":1,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43099\/revisions"}],"predecessor-version":[{"id":159029,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/43099\/revisions\/159029"}],"wp:attachment":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/media?parent=43099"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/categories?post=43099"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/tags?post=43099"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}