{"id":42084,"date":"2023-03-28T07:39:34","date_gmt":"2023-03-28T02:09:34","guid":{"rendered":"https:\/\/icsesolutions.com\/?p=42084"},"modified":"2023-03-29T09:36:26","modified_gmt":"2023-03-29T04:06:26","slug":"ml-aggarwal-class-6-solutions-for-icse-maths-chapter-2-ex-2-2","status":"publish","type":"post","link":"https:\/\/icsesolutions.com\/ml-aggarwal-class-6-solutions-for-icse-maths-chapter-2-ex-2-2\/","title":{"rendered":"ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 2 Whole Numbers Ex 2.2"},"content":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 2 Whole Numbers Ex 2.2<\/h2>\n

Question 1.
\nFill in the blanks to make each of the following a true statement:
\n(i) 378 + 1024 = 1024 + …….
\n(ii) 337 + (528 + 1164) = (337 + ……..) + 1164
\n(iii) (21 + 18) + ……….. = (21 + 13) + 18
\n(iv) 3056 + 0 = ……….. = 0 + 3056
\nSolution:
\n(i) 378 + 1024= 1024 + 378 (Commutative property of addition)
\n(ii) 337 + (528 + 1164) = (337 + 528) + 1164 (Associative law of addition)
\n(iii) (21 + 18) + 13 = (21 + 13) + 18 (Associative law of addition)
\n(iv) 3056 + 0 = 3056 = 0 + 3056<\/p>\n

Question 2.
\nAdd the following numbers and check by reversing the order of addends :
\n(i) 3189 + 53885
\n(ii) 33789 + 50311.
\nSolution:
\n(i) 3189 + 53885 = 57074
\nCheck 53885 + 3189 = 57074
\n\u223457074<\/p>\n

(ii) 33789 + 50311 = 84100
\nCheck 50311 + 33789 = 84100
\n\u2234 84100<\/p>\n

Question 3.
\nBy suitable arrangements, find the sum of:
\n(i) 311,528,289
\n(ii) 723, 834, 66, 277
\n(iii) 78, 203, 435, 7197, 422.
\nSolution:
\n(i) 311, 528, 289
\nSum (311 +289)+ 528
\n= 600+ 528= 1128<\/p>\n

(ii) 723 + 834 + 66 + 277
\n= (723 + 277) + (834 + 66)
\n= 1000 + 900 = 1900<\/p>\n

(iii) 78, 203, 435, 7197, 422
\nSum = (78 + 422) + (203 + 7197) + 435
\n= 500 + 7400 + 435
\n= 7900 + 435 = 8335<\/p>\n

Question 4.
\nFill in the blanks to make each of the following a true statement:
\n(i) 375 \u00d7 57 = 57 \u00d7 ……….
\n(ii) (33 \u00d7 16) \u00d7 25 = 33 \u00d7 (…….. \u00d7 25)
\n(iii) 37 \u00d7 24 = 37 \u00d7 18 + 37 \u00d7 …………
\n(iv) 7205 \u00d7 1 = …………. = 1 \u00d7 7205
\n(v) 366 \u00d7 0 =
\n(vi) …………… \u00d7 579 = 0
\n(vii) 473 \u00d7 108 = 473 \u00d7 100 + 473 \u00d7 ………….
\n(viii) 684 \u00d7 97 = 684 \u00d7 100 – …………… \u00d7 3
\n(ix) 0 \u00f7= 5 =
\n(x) (14 – 14) \u00f7 7 = ………….
\nSolution:
\n(i) 375 \u00d7 57 = 57 \u00d7 375 (Commutative property of multiplication)
\n(ii) 33 \u00d7 16) \u00d7 25 = 33 \u00d7 (16 \u00d7 25) (Associative law of multiplication)
\n(iii) 37 \u00d7 24 = 37 \u00d7 18 + 37 \u00d7 6 (Distributive law of multiplication)
\n(iv) 7205 \u00d7 1 = 7205 = 1 \u00d7 7205
\n(v) 366 \u00d7 0 = 0
\n(vi) 0 \u00d7 579 = 0
\n(vii) 473 \u00d7 108 = 473 \u00d7 100 + 473 \u00d7 8
\n(viii) 684 \u00d7 97 = 684 \u00d7 100 – 684 \u00d7 3
\n(ix) 0 \u00f7 5 = 0
\n(x) (14 – 14) \u00f7 7 = 0<\/p>\n

Question 5.
\nDetermine the following products by suitable arrangement:
\n(i) 4 \u00d7 528 \u00d7 25
\n(ii) 625 \u00d7 239 \u00d7 16
\n(iii) 125 \u00d7 40 \u00d7 8 \u00d7 25
\nSolution:
\n(i) 4 \u00d7 528 \u00d7 25 = 4 \u00d7 25 \u00d7 528
\n= 100 \u00d7 528 = 52800<\/p>\n

(ii) 625 \u00d7 239 \u00d7 16 = 625 \u00d7 16 \u00d7 239
\n= 10000 \u00d7 239 = 2390000<\/p>\n

(iii) 125 \u00d7 40 \u00d7 8 \u00d7 25 = 125 \u00d7 8 \u00d7 40 \u00d7 25
\n= 1000 \u00d7 1000 = 1000000<\/p>\n

Question 6.
\nFind the value of the following:
\n(i) 54279 \u00d7 92 + 54279 \u00d7 8
\n(ii) 60678 \u00d7 262 – 60678 \u00d7 162
\nSolution:
\n(i) 54279 \u00d7 92 + 54279 \u00d7 8
\n= 54279 (92 + 8)
\n= 54279 \u00d7 100 = 5427900<\/p>\n

(ii) 60678 \u00d7 262 – 60678 \u00d7 162
\n= 60678 (262 – 162)
\n= 60678 \u00d7 100 = 6067800<\/p>\n

Question 7.
\nFind the following products by using suitable properties:
\n(i) 739 \u00d7 102
\n(ii) 1938 \u00d7 99
\n(iii) 1005 \u00d7 188
\nSolution:
\n(i) 739 \u00d7 102
\n= 739 \u00d7 (100 + 2)
\n= 739 \u00d7 100 + 739 \u00d7 2
\n= 73900 + 1478 = 75378<\/p>\n

(ii) 1938 \u00d7 99
\n= 1938 \u00d7 (100- 1)
\n= 1938 \u00d7 100 – 1938 \u00d7 1
\n= 193800 – 1938 = 191862<\/p>\n

(iii) 1005 \u00d7 188
\n= (1000 + 5) \u00d7 (100 + 88)
\n= 1000 \u00d7 100 + 1000 \u00d7 88 + 5 \u00d7 100 + 88 \u00d7 5
\n= 100000 + 88000 + 500 + 440 = 188940<\/p>\n

Question 8.
\nDivide 7750 by 17 and check the result by division algorithm.
\nSolution:
\n7750 \u00f7 17
\n\"ML
\nOn dividing 7750 by 17, we get
\nQuotient = 455 and Remainder = 15
\nCheck by division algorithm:
\nDivident = Divisior \u00d7 Quotient + Remainder
\n= 17 \u00d7 455 + 15 = 7750<\/p>\n

Question 9.
\nFind the number which when divided by 38 gives the quotient 23 and remainder 17.
\nSolution:
\nDivisor = 38,Quotient = 23
\nRemainder = 17
\nDividend = divisor \u00d7 quotient + remainder
\n= 38 \u00d7 23 + 17 = 874 + 17 = 891<\/p>\n

Question 10.
\nWhich least number should be subtracted from 1000 so that the difference is exactly divisible by 35.
\nSolution:
\nOn dividing 1000 by 35
\nwe get quotient = 28 and remainder 20
\n\"ML
\nSo, 20 should be subtracted from 1000.<\/p>\n

Question 11.
\nWhich least number should be added to 1000 so that 53 divides the sum exactly.
\nSolution:
\n\"ML
\nOn dividing 1000 by 53, we get quotient = 18 and remainder = 46. To get the remainder 0, we should add 53 – 46 = 7 to 1000.
\n\u2234 7<\/p>\n

Question 12.
\nFind the largest three-digit number which is exactly divisible by 47.
\nSolution:
\nLargest three digit no. = 999
\n\"ML
\nOn dividing 999 by 47, we get
\nQuotient = 21 and Remainder =12
\nSo on subtracting 12 from 999, we get
\n999 – 12 = 987<\/p>\n

Question 13.
\nFind the smallest five-digit number which is exactly divisible by 254.
\nSolution:
\nSmallest 5 digit number = 10000
\n\"ML
\nOn dividing 10000 by 254, we get
\nRemainder = 94
\nSo 254 – 94 = 160 should be added to 10000 to get the smallest 5 digit number divisible by 254.
\n\u2234 10000 + 160 = 10160<\/p>\n

Question 14.
\nA vendor supplies 72 litres of milk to a student’s hostel in the morning and 28 litres of milk in the evening every day. If the milk costs?39 per litre, how much money is due to the vendor per day?
\nSolution:
\nSupply of milk in morning = 72 litres
\nSupply of milk in evening = 28 litres
\nCost of per litre milk = \u20b9 39
\nMoney of per day = \u20b9 39 (72 l + 28 l)
\n= \u20b9 39 \u00d7 100 = \u20b9 3900<\/p>\n

Question 15.
\nState whether the following statements are true (T) or false (F):
\n(i) If the product of two whole numbers is zero, then atleast one of them will be zero.
\n(ii) If the product of two whole numbers is 1, then each of them must be equal to 1.
\n(iii) If a and b are whole numbers such that a \u2260 0 and b \u2260 0, then ab may be zero.
\nSolution:
\n(i) True
\n(ii) True
\n(iii)False<\/p>\n

Question 16.
\nReplace each * by the correct digit in each of the following:
\n\"ML
\nSolution:
\n\"ML
\n\"ML<\/p>\n

ML Aggarwal Class 6 Solutions for ICSE Maths<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"

ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 2 Whole Numbers Ex 2.2 Question 1. Fill in the blanks to make each of the following a true statement: (i) 378 + 1024 = 1024 + ……. (ii) 337 + (528 + 1164) = (337 + ……..) + 1164 (iii) (21 + 18) + ……….. …<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[3034],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/42084"}],"collection":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/comments?post=42084"}],"version-history":[{"count":1,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/42084\/revisions"}],"predecessor-version":[{"id":158919,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/posts\/42084\/revisions\/158919"}],"wp:attachment":[{"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/media?parent=42084"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/categories?post=42084"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/icsesolutions.com\/wp-json\/wp\/v2\/tags?post=42084"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}