{"id":19190,"date":"2023-02-05T08:08:01","date_gmt":"2023-02-05T02:38:01","guid":{"rendered":"https:\/\/icsesolutions.com\/?p=19190"},"modified":"2023-02-06T10:20:32","modified_gmt":"2023-02-06T04:50:32","slug":"frank-icse-solutions-class-9-physics-measurement","status":"publish","type":"post","link":"https:\/\/icsesolutions.com\/frank-icse-solutions-class-9-physics-measurement\/","title":{"rendered":"Frank ICSE Solutions for Class 9 Physics – Measurement"},"content":{"rendered":"
PAGE NO: 15<\/strong><\/span> Solution 2:<\/strong><\/span> Solution 3:<\/strong><\/span> Solution 4:<\/strong><\/span> Solution 5:<\/strong><\/span> Solution 6:<\/strong><\/span> Solution 7:<\/strong><\/span> Solution 8:<\/strong><\/span> Solution 9:<\/strong><\/span> Solution 10:<\/strong><\/span> Solution 11:<\/strong><\/span> Solution 12:<\/strong><\/span> Solution 13:<\/strong><\/span> Solution 14:<\/strong><\/span> Solution 15:<\/strong><\/span> Solution 16:<\/strong><\/span> Solution 17:<\/strong><\/span> PAGE NO: 16<\/strong><\/span> Solution 19:<\/strong><\/span> Solution 20:<\/strong><\/span> PAGE NO: 28<\/strong><\/span> Solution 2:<\/strong><\/span> Solution 3:<\/strong><\/span> Solution 4:<\/strong><\/span> Solution 5:<\/strong><\/span> Solution 6:<\/strong><\/span> PAGE NO: 29<\/strong><\/span> Solution 8:<\/strong><\/span> Solution 9:<\/strong><\/span> Solution 10:<\/strong><\/span> Solution 11:<\/strong><\/span> Solution 12:<\/strong><\/span> Solution 13:<\/strong><\/span> Solution 14:<\/strong><\/span> Solution 15:<\/strong><\/span> Solution 16:<\/strong><\/span> Solution 17:<\/strong><\/span> Solution 18:<\/strong><\/span> Solution 19:<\/strong><\/span> Solution 20:<\/strong><\/span> Solution 21:<\/strong><\/span><\/p>\n Solution 22:<\/strong><\/span> Solution 23:<\/strong><\/span> Solution 24:<\/strong><\/span> PAGE NO: 30<\/strong><\/span> Solution 26:<\/strong><\/span> Solution 27:<\/strong><\/span> Solution 28:<\/strong><\/span> Solution 29:<\/strong><\/span> Solution 30:<\/strong><\/span> PAGE NO: 38<\/strong><\/span> Solution 2:<\/strong><\/span> Solution 3:<\/strong><\/span> Solution 4:<\/strong><\/span> Solution 5:<\/strong><\/span> Solution 6:<\/strong><\/span> Solution 7:<\/strong><\/span> Solution 8:<\/strong><\/span> Solution 9:<\/strong><\/span> Solution 10:<\/strong><\/span> Solution 11:<\/strong><\/span> Solution 12:<\/strong><\/span> Solution 13:<\/strong><\/span>
\nSolution 1:<\/strong><\/span>
\nMeasurement is an act or the result of comparison of a quantity whose magnitude is unknown with a predefined standard.<\/p>\n
\nThe physical quantities like mass, length and time which do not depend on each other are known as fundamental quantities.<\/p>\n
\nLength, mass, time are the three fundamental quantities.<\/p>\n
\nUnit is a standard quantity of the same kind with which a physical quantity is compared for measuring it.<\/p>\n
\nA standard metreis equal to 1650763.73 wavelengths in vacuum, of the radiation from krypton isotope of mass 86.<\/p>\n
\nThree systems of unit are<\/p>\n\n
\nThe SI unit of mass is Kilogram. One standard kilogram is equal to the mass of a cylinder of nearly same height and diameter and made up of platinum and iridium alloy.<\/p>\n
\nThree units of length greater than a metre are<\/p>\n\n
\n<\/p>\n
\nLight year is defined as the distance travelled by light in vacuum in one year.<\/p>\n
\nTwo units of length smaller than a metre are<\/p>\n\n
\nLeap year because it is a unit of time.<\/p>\n
\nOrder of magnitude of a physical quantity is defined as its magnitude in powers of ten when that physical quantity is expressed in powers of ten with one digit towards the left decimal.
\nFor example, volume= 52.37 m3<\/sup> then the order of magnitude is 102<\/sup>m3<\/sup>.<\/p>\n
\nNo, micron is not same as millimeter because micron is equal to 10-6<\/sup>metre while a millimeter is equal to 10-3<\/sup>metre.<\/p>\n
\n<\/p>\n
\n<\/p>\n
\nA leap year refers to a year in which February has 29 days and the total days in the year are 366 days.<\/p>\n
\nSolution 18:<\/strong><\/span>
\n<\/p>\n
\n<\/p>\n
\n<\/p>\n
\nSolution 1:<\/strong><\/span>
\nWhen one complete rotation is given to the screw hand, it moves forward or backward by a distance is called pitch of the screw. It is distance between two consecutive threads of the screw.
\nPitch of the screw = distance travelled by screw in n rotations\/n rotations<\/p>\n
\nNo, least count is not same as pitch because least count is found by dividing pitch by number of divisions on the circular scale.<\/p>\n
\nTwo uses of vernier caliper are<\/p>\n\n
\nTwo limitations of metre rule<\/p>\n\n
\nWhen one complete rotation is given to the screw hand, it moves forward or backward by a distance called pitch of the screw. It is distance between two consecutive threads of the screw.
\nPitch of the screw = distance travelled by screw in n rotations\/n rotations
\nLeast count refers to the smallest reading that can be accurately measured while using an instrument. The least count is the value of one division on its scale.<\/p>\n
\nInitial level of water in cylinder = 30 ml
\nLevel of water in cylinder after immersing piece of copper = 50 ml
\nVolume of copper piece = 50-30 = 20 ml<\/p>\n
\nSolution 7:<\/strong><\/span>
\n<\/p>\n
\nThe ratchet is used in a screw gauge to hold the object under measurement gently between the studs.<\/p>\n
\nIf the zero of the circular scale does not coincide with the zero of the main scale (pitch scale), this is known as zero error. There are two types of zero error –<\/p>\n\n
\nFor positive zero error correction, the zero error should always be subtracted from the observed reading
\nFor negative zero error correction, the zero error must be added to the observed reading.<\/li>\n<\/ol>\n
\nTwo scales in a screw gauge are<\/p>\n\n
\nDue to constant use, there is space for the play of screw gauge but gradually this space increases with the use or wear and tear, so that when the screw is moved by rotating it in some direction, it slips in the nut and does not cover any linear distance for some rotation of the screw head. The error due to this is known as backlash error.
\nIt is avoided by turning the screw always in the same direction.<\/p>\n
\nFollowing procedure is used to measure the diameter of a wire<\/p>\n\n
\n<\/p>\n
\nScrew gauge measures a small length to a high accuracy because it has the lowest least count among the given three instruments. And low least count means high accuracy<\/p>\n
\n<\/p>\n
\n<\/p>\n
\n<\/p>\n
\nIf the zero of the circular scale remains below the line of graduation then it is called positive zero error. When there is positive zero error, then the instrument reads more than the actual reading. Therefore in order to get the correct reading, the zero error should always be subtracted from the observed reading.<\/p>\n
\nPitch of the screw gauge = 0.5mm = 0.05 cm
\nCircular scale divisions = 100
\nLeast Count of screw gauge = pitch of the gauge\/circular scale divisions
\n= 0.05\/100
\n= 0.0005cm<\/p>\n
\nIf the zero of the circular scale lies above the line of graduation then it is called negative zero error. When there is negative zero error, then the instrument reads less than the actual reading. Therefore in order to get the correct reading, the zero error should always be added to the observed reading.<\/p>\n\n
\nThe space occupied by a body is known as its volume. SI unit of volume is cubic metre (m3<\/sup>)<\/p>\n
\nThe space occupied by a body is known as its volume. SI unit of volume is cubic metre (m3<\/sup>)<\/p>\n
\n1 m3<\/sup>\u00a0= 1000 litre
\n1 litre = 1\/1000 m3<\/sup>
\n= 0.001 m3<\/sup><\/p>\n
\nSolution 25:<\/strong><\/span>
\n<\/p>\n
\nSI unit of volume is cubic metre or metre3<\/sup> (m3<\/sup>).
\nThe relation between liter and metre3<\/sup>
\n1 metre3<\/sup> = 1000 liter<\/p>\n
\nPitch of the screw = 0.5 mm
\nLeast count = 0.001 mm
\nNumber of divisions = pitch\/least count
\n= 0.5\/0.001
\n= 500<\/p>\n
\n<\/p>\n
\nPrecautions to be taken while measuring volume of a solid lighter than water using displacement method<\/p>\n\n
\nMeasurement of volume of an irregular solid soluble in water using a graduated cylinder.<\/p>\n\n
\nSolution 1:<\/strong><\/span>
\n<\/p>\n
\nA seconds pendulum is a pendulum which takes 2 seconds to complete one oscillation. The length of seconds pendulum, where g = 9.8ms-2<\/sup>, is nearly 1 m.<\/p>\n
\nA stopwatch is used to measure short intervals of time.<\/p>\n
\nSI unit of frequency is hertz (Hz).<\/p>\n
\nWhen a pendulum completes one oscillation in one second, then the frequency is one hertz.<\/p>\n
\nThe time period, T and frequency of oscillation, f are related as,
\nT = 1\/f or f = 1\/T<\/p>\n
\nOne complete to and fro motion of a pendulum about its mean position is known as oscillation. Amplitude is the magnitude of the maximum displacement of the bob from the mean position on either side when an oscillation takes place.<\/p>\n
\nSI unit of amplitude is metre (m).<\/p>\n
\nA seconds pendulum is a pendulum which takes 2 seconds to complete one oscillation. The length of seconds pendulum, where g = 9.8ms-2<\/sup>, is nearly 1 m.<\/p>\n
\n<\/p>\n
\n<\/p>\n
\nWhen a pendulum is taken from earth to moon surface, its time period will increase because the acceleration due to gravity on moon is less than that on earth and the time period depends inversely on square root of acceleration due to gravity.<\/p>\n
\nIf time period of a pendulum becomes infinite, the pendulum will not oscillate at all as pendulum will take infinite time to complete one oscillation.<\/p>\n