Selina ICSE Solutions for Class 9 Maths Chapter 20 Area and Perimeter of Plane Figures<\/strong><\/p>\nExercise 20(A)<\/strong><\/span><\/p>\nSolution 1:<\/strong><\/span>
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\nSince the perimeter of the isosceles triangle is 36cm and base is 16cm.
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\n<\/p>\nExercise 20(B)<\/strong><\/span><\/p>\nSolution 1:<\/strong><\/span>
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\nWe need to find the cost of carpeting of 80 cm = 0.8 m wide carpet, if the rate of carpeting is Rs. 25. Per metre.
\nThen
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\nIn the given figure, we can observe that the non-parallel sides are equal and hence it is an isosceles trapezium.
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\n<\/p>\nExercise 20(C)<\/strong><\/span><\/p>\nSolution 1:<\/strong><\/span>
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\nFrom the given data, we can calculate the area of the outer circle and then the area of inner circle and hence the width of the shaded portion.
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\n<\/p>\nMore Resources for Selina Concise Class 9 ICSE Solutions<\/strong><\/p>\n