## ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Objective Type Questions

**Mental Maths**

Question 1.

Fill in the blanks:

(i) In fractions with same numerator, the fraction with greater denominator is …….

(ii) \(\frac { 114 }{ 138 }\) reduced to simplest forms is ………

(iii) \(\frac { 154 }{ 286 }\) = \(\frac { …… }{ 13 }\)

(iv) The reciprocal of the fraction 2\(\frac { 3 }{ 8 }\) is …….

(v) There are …….. minutes in \(\frac { 2 }{ 5 }\) th of 2 hours.

(vi) 2\(\frac { 3 }{ 7 }\) × 4\(\frac { 2 }{ 3 }\) = …….

(vii) 1\(\frac { 2 }{ 3 }\) ÷ 2\(\frac { 1 }{ 5 }\) = ………

(viii) If the price of 7 similar pens is ₹ 37.80, then the price of each pen is ……..

(ix) 5.4 × 2.35 = ……

(x) 0.32 ÷ 8 = …….

(xi) 45 mg = ………. g

(xii) 5.06 kg = ……… kg …….. g

(xiii) 7.035 m = ……. m …….. cm …….. mm

(xiv) The product of a proper fraction and an improper fraction is …… the improper fraction.

(xv) The lowest form of the product 2\(\frac { 3 }{ 7 }\) × \(\frac { 7 }{ 9 }\) is ………

(xvi) Ravi ate \(\frac { 2 }{ 7 }\) part of a cake while his sister Rani ate \(\frac { 4 }{ 5 }\) of the remaining. Part of the cake left is ……

Solution:

(i) In fractions with same numerator, the fraction with greater denominator is smaller.

(ii) \(\frac { 114 }{ 138 }\) reduced to simplest forms is \(\frac { 19 }{ 23 }\). {Dividing each by 6}

(iii) \(\frac { 154 }{ 286 }\) = \(\frac { 7 }{ 13 }\) {Dividing each by 22}

(iv) The reciprocal of the fraction 2\(\frac { 3 }{ 8 }\) is \(\frac { 8 }{ 19 }\).

{∵ 2\(\frac { 3 }{ 8 }\) = \(\frac { 19 }{ 8 }\)}

(v) There are 48 minutes in \(\frac { 2 }{ 5 }\)th of 2 hours.

Question 2.

State whether the following statements are true (T) or false (T):

(i) The reciprocal of 1 is 0.

(ii) The reciprocal of a proper fraction is a proper fraction.

(iii) The reciprocal of an improper fraction is an improper fraction.

(iv) Product of two fractions

(x) The product of two proper fractions is greater than each of the two fractions.

(xi) To multiply a decimal number by 10, move the decimal point to the left by one place.

(xii) To divide a decimal number by 100, move the decimal point to the left by two places.

Solution:

(i) The reciprocal of 1 is 0. (False)

Correct:

Reciprocal of 1 is 1.

(ii) The reciprocal of a proper fraction is a proper fraction. (False)

Correct:

It is an improper fraction.

(iii) The reciprocal of an improper fraction is an improper fraction. (False)

Correct:

It is a proper fraction.

(xi) To multiply a decimal number by 10, move the decimal point to the left by one place. (False)

Correct:

(Move one point to the right not left)

(xii) To divide a decimal number by 100, move the decimal point to the left by two places. (True)

**Multiple Choice Questions**

Choose the correct answer from the given four options (3 to 20):

Question 3.

\(\frac { 5 }{ 6 }\) of 480 is

(a) 400

(b) 576

(c) 480

(d) none of these

Solution:

\(\frac { 5 }{ 6 }\) of 480 = \(\frac { 5 }{ 6 }\) × 480 = 400 (a)

Question 4.

The reciprocal of 5\(\frac { 2 }{ 3 }\) is

(a) 5\(\frac { 3 }{ 2 }\)

(b) 3\(\frac { 2 }{ 5 }\)

(c) 2\(\frac { 3 }{ 5 }\)

(d) \(\frac { 3 }{ 17 }\)

Solution:

Reciprocal of 5\(\frac { 2 }{ 3 }\) or \(\frac { 17 }{ 3 }\) is \(\frac { 3 }{ 17 }\) (d)

Question 5.

The fraction \(\frac { 11 }{ 7 }\) lies between

(a) 11 and 7

(b) 1 and 2

(c) 0 and 1

(d) 2 and 3

Solution:

The fraction \(\frac { 11 }{ 7 }\) = 1\(\frac { 4 }{ 7 }\) lies between 1 and 2 (b)

Question 6.

If the cost of 1 kg almonds is ₹ 460, then the cost of \(\frac { 2 }{ 5 }\) kg of almonds is

(a) ₹ 92

(b) ₹ 184

(b) ₹ 230

(d) ₹ 1200

Solution:

Cost of 1 kg almonds = ₹ 460

Cost of \(\frac { 2 }{ 5 }\) kg = ₹ 460 × \(\frac { 2 }{ 5 }\) = ₹ 184

Question 7.

Solution:

Question 8.

Solution:

Question 9.

If \(\frac { 3 }{ 4 }\) of a number is 12, then the number is

(a) 9

(b) 16

(c) 18

(d) 32

Solution:

If \(\frac { 3 }{ 4 }\) of a number = 12

Then number = 12 × \(\frac { 4 }{ 3 }\) = 16 (b)

Question 10.

Arif bought 3 dozen eggs. He found \(\frac { 1 }{ 9 }\) of them were rotten. The number of rotten eggs was

(a) 4

(b) 3

(c) 6

(d) 8

Solution:

Total eggs = 3 dozen = 3 × 12 = 36

Number of rotten = \(\frac { 1 }{ 9 }\) of 36 = 4 (a)

Question 11.

Shruti reads a novel for 1\(\frac { 3 }{ 4 }\) hours daily, if she reads the entire novel in 6 days, then the time she takes to read the entire novel is

(a) 7\(\frac { 1 }{ 2 }\) hours

(b) 9\(\frac { 1 }{ 2 }\) hours

(c) 10\(\frac { 1 }{ 2 }\) hours

(d) 11\(\frac { 1 }{ 2 }\) hours

Solution:

A novel is read per day = 1\(\frac { 3 }{ 4 }\) = \(\frac { 7 }{ 4 }\) hours

Novel is read in 6 days

Total time = \(\frac { 7 }{ 4 }\) × 6 = \(\frac { 21 }{ 2 }\) = 10\(\frac { 1 }{ 2 }\) (c)

Question 12.

The place value of the digit 7 in the decimal number 35.0471 is

(a) 7

(b) \(\frac { 7 }{ 100 }\)

(c) \(\frac { 1 }{ 1000 }\)

(d) \(\frac { 7 }{ 1000 }\)

Solution:

Place value of 7 in 35.0471 = \(\frac { 7 }{ 1000 }\) (d)

Question 13.

0.002 × 0.3 is

(a) 0.6

(b) 0.06

(c) 0.006

(d) 0.006

Solution:

0.002 × 0.3 = 0.006 (d)

Question 14.

The value of the mixed fraction 5\(\frac { 3 }{ 8 }\) is

(a) 5.735

(b) 5.375

(c) 5.625

(d) 5.875

Solution:

Question 15.

0.35 ÷ 0.7 is

(a) 50

(b) 5

(c) 0.5

(d) 0.05

Solution:

0.35 ÷ 0.7 = 0.5 (c)

Question 16.

30 m 5 cm is same as

(a) 30.5 m

(b) 3.05 m

(c) 30.05 m

(d) 30.005 m

Solution:

30 m 5 cm = 30.05 m (c)

Question 17.

0.05309 × 1000 is

(a) 5.309

(b) 53.09

(c) 530.9

(d) none of these

Solution:

0.05309 × 1000 = 53.09 (b)

Question 18.

2.305 ÷ 1000 is

(a) 0.2305

(b) 0.02305

(c) 0.002305

(d) none of these

Solution:

2.305 ÷ 1000 = 0.002305 (c)

Question 19.

If each side of a regular hexagon is 3.5 cm, then the perimeter of the hexagon is

(a) 17.5 cm

(b) 21 cm

(c) 18.5 cm

(d) 24.5 cm

Solution:

Each side of a regular hexagon = 3.5 cm

Its perimeter = 3.5 × 6 = 21 cm (b)

Question 20.

Which of the following numbers has the smallest value?

(a) 0.0002

(b) \(\frac { 2 }{ 1000 }\)

(c) 0.02 × 0.001

(d) \(\frac { 2 }{ 1000 }\) ÷ 0.01

Solution:

**Value Based Questions**

Question 1.

Seema had one sandwich for her lunch and her two other friends in the class forgot to bring their lunch. Seema decided to share equally her sandwich with her friends. How much part of the sandwich each girl will get? What have you learnt by this behaviour of Seema?

Solution:

One sandwich is to be divided equally in 3 equal parts.

Each part = \(\frac { 1 }{ 3 }\)

We should take care of the needs of others also. It is a good habit.

Question 2.

A farmer had a large field of dimensions 1396.5 m by 272.72 m. Find the area of the field. He left \(\frac { 1 }{ 6 }\) of this area to make a playground for the children of the locality. Find the area of the playground. Which value of the farmer is reflected in this act?

Solution:

Length of a field = 1396.5 m

and Breadth = 272.72 m

Area of the field = Length × Breadth

= 1396.5 × 272.72 sq m

= 380853.48 sq m

Area left for playground = \(\frac { 1 }{ 6 }\) of 380853.48

= 63475.58 sq m

**Higher Order Thinking Skills (HOTS)**

Question 1.

I read \(\frac { 4 }{ 9 }\) of a book on one day and \(\frac { 3 }{ 5 }\) of the remaining next day. If 100 pages of the book were still left unread, how many pages did the book contain?

Solution:

Portion of the book, read on one day = \(\frac { 4 }{ 9 }\) part

Question 2.

A drum of petrol is \(\frac { 3 }{ 4 }\) full. When 30 litres of oil are drawn from it, it is \(\frac { 7 }{ 12 }\) full. Find the capacity of the drum.

Solution:

Petrol in a drum = \(\frac { 3 }{ 4 }\) part

After drawning 30 litres of petrol, the remaining petrol = \(\frac { 7 }{ 12 }\) part

\(\frac { 3 }{ 4 }\) – \(\frac { 7 }{ 12 }\) = 30 litres