ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6

Question 1.
Find the following:
(i) 2.7 × 4
(ii) 2.71 × 5
(iii) 2.5 × 0.3
(iv) 2.3 × 4.35
(v) 238.06 × 7.5
(vi) 0.79 × 32.4
(vii) 1.07 × 0.02
(viii) 10.05 × 1.05
Solution:
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 1.1
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 1.2
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 1.3

Question 2.
find the following:
(i) 10.8 ÷ 4
(ii) 126.35 ÷ 7
(iii) 22.5 ÷ 1.5
(iv) 4.28 ÷ 0.02
(v) 3.645 ÷ 1.35
(vi) 0.728 ÷ 0.04
(vii) 13.06 ÷ 0.08
(viii) 58.635 ÷ 4.5
Solution:
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 2.1
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 2.2
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 2.3

Question 3.
Multiply each of the following numbers by 10, 100 and 1000 (orally):
(i) 5.9
(ii) 3.76
(iii) 0.549
Solution:
(i) 5.9 × 10 = 59
5.9 × 100 = 590
5.9 × 1000 = 5900
(ii) 3.76 × 10 = 37.6
3.76 × 100 = 376
3.76 × 1000 = 3760
(iii) 0.549 × 10 = 5.49
0.549 × 100 = 54.9
0.549 × 1000 = 549

Question 4.
Divide each of the following numbers by 10, 100 and 1000 (orally):
(i) 4.8
(ii) 38.53
(iii) 128.9
Solution:
(i) 4.8
4.8 ÷ 10 = 0.48
4.8 ÷ 100 = 0.048
4.8 ÷ 1000 = 0.0048
(ii) 38.53
38.53 ÷ 10 = 3.853
38.53 ÷ 100 = 0.3853
38.53 ÷ 1000 = 0.03853
(iii) 128.9
128.9 ÷ 10 = 12.89
128.9 ÷ 100 = 1.289
128.9 ÷ 1000 = 0.1289

Question 5.
Find the area of a rectangle whose length is 5.7 cm and breadth is 3.5 cm.
Solution:
Length of a rectangle = 5.7 cm
and Breadth = 3.5 cm
Area = Length × Breadth
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 5.1
= 5.7 × 3.5 sq. cm
= 19.95 sq. cm

Question 6.
The cost of one metre cloth is ₹ 38.50. Find the cost of 3.6 m cloth.
Solution:
Cost of one metre of cloth = ₹ 38.50
Cost of 3.6 m of cloth = ₹ 38.50 × 3.6
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 6.1
= ₹ 138.600
= ₹ 138.60

Question 7.
A two-wheeler covers a distance of 45.3 km in one litre of petrol. How much distance will it cover in 5.9 litres of petrol?
Solution:
In 1 litre of petrol, a two-wheeler cover = 45.3
In 3.9 litre of petrol, it will cover a distance of = 45.3 × 3.9 = 176.67 km
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 7.1

Question 8.
If 1 kg of pure milk contains 0.245 kg of fat. How much fat is there in 12.8 kg of milk?
Solution:
In 1 kg of milk, fats is = 0.245 kg
Then in 12.8 kg of milk, fats will be
= 0.245 × 12.8 kg
= 3.1360 kg
= 3.136 kg
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 8.1

Question 9.
If ₹ 242.46 are to be distributed among 6 children equally, find the share of each.
Solution:
6 children gets = ₹ 242.46
One child will get = ₹ 242.46 ÷ 6 = ₹ 40.41

Question 10.
A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?
Solution:
In 2.4 litres of petrol, a vehicle covers a distance = 43.2 km
It will cover a distance in one Jtre of petrol = 43.2 ÷ 2.4 km
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 10.1

Question 11.
How many ice cream cones can be filled from 8.4 litres of ice cream if one cone can be filled with 35 millilitres of ice cream?
Solution:
In one cone, 35 millilitres of ice cream is filled
In 8.4 litres of ice cream will be filled
(8.4 l = 8.4 × 100 ml)
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 11.1

Question 12.
If the product of two decimal numbers is 38.745 and one of the numbers is 2.7, find the other.
Solution:
Product of two decimal numbers = 38.745
One number = 2.7
Second number = 38.745 ÷ 2.7
ML Aggarwal Class 7 Solutions for ICSE Maths Chapter 2 Fractions and Decimals Ex 2.6 12.1

Question 13.
If \(\frac { 2 }{ 3 }\) of a number is 10, then what is 1.75 times of that number?
Solution:
\(\frac { 2 }{ 3 }\) of a number = 10
Number = \(\frac { 10\times 3 }{ 2 }\) = 15
and 1.75 times of the number =15 × 1.75 = 26.25

ML Aggarwal Class 7 Solutions for ICSE Maths

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