## ML Aggarwal Class 6 Solutions for ICSE Maths Chapter 6 Fractions Ex 6.1

Question 1.

Write the following division as fractions:

(i) 3 ÷ 7

(ii) 11 ÷ 78

(iii) 113 ÷ 128

Solution:

(i) 3 ÷ 7 = \(\frac{3}{7}\)

(ii) 11 ÷ 78 = \(\frac{11}{78}\)

(iii) 113 ÷ 128 = \(\frac{113}{128}\)

Question 2.

Write the following fractions in words.

(i) \(\frac{2}{7}\)

(ii) \(\frac{3}{10}\)

(iii) \(\frac{15}{28}\)

Solution:

(i) \(\frac{2}{7}\) = Two – Seventh

(ii) \(\frac{3}{10}\) = Three – Tenth

(iii) \(\frac{15}{28}\) fifteen – Twenty eighth

Question 3.

Write the following fractions in number form:

(i) one – sixth

(ii) three – eleventh,

(iii) seven-fortieth

(iv) thirteen – one hundred twenty fifth

Solution:

(i) One – sixth = \(\frac{1}{6}\)

(ii) Three-eleventh = \(\frac{3}{11}\)

(iiii) seven-forteith = \(\frac{7}{40}\)

(iv) Thirteen-one hundred twenty fifth = \(\frac{13}{125}\)

Question 4.

What fraction of each of the following is shaded part?

Solution:

Question 5.

Shade the parts of the following figures according to given fractions:

Solution:

Question 6.

In the adjoining figure, if we say that the shaded region is \(\frac{1}{4}\) of the whole region, then identify the error in it.

Solution:

The whole rectangle is not divided into four equal parts.

Question 7.

Write the fraction in which

(i) numerator = 5 and denominator = 13

(ii) denominator = 23 and numerator = 17

Solution:

(i) \(\frac{5}{13}\)

(ii) \(\frac{17}{23}\)

Question 8.

Shabana has to stitch 35 dresses. So, ar she has stitched 21 dresses. What fraction of dresses has she stitched?

Solution:

Number of dresses she had to stiches = 35

Number of dresses she has finished = 21

∴ Fraction of dresses she has finished = \(\frac{21}{35}=\frac{3}{5}\)

Question 9.

What fraction of a day is 8 hours ?

Solution:

Number of hours in a day = 24 hours

∴ Required fraction = \(\frac{8}{24}\)

Question 10.

What fraction of an hour is 45 minutes ?

Solution:

An hour (1 hour) = 60 minutes

∴ Required fraction = \(\frac{45}{60}\)

Question 11.

How many natural numbers are there from 87 to 97? What fraction of them are prime numbers?

Solution:

The natural numbers from 87 to 97 are 87, 88, 89, 90, 91, 92, 93, 94, 95, 96 and 97. Total number of natural number = 11 Out of these, the prime numbers are 87 and 97

Total number of these prime numbers = 2

∴ Required fraction = \(\frac{2}{11}\)